document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=168126>Question 168126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't understand it says to solve by the addition or subtraction method<BR>\n" );
document.write( "2x+y=18<BR>\n" );
document.write( "2x-y=22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123898 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you add these 2 equations together you would be adding the x terms to x terms the y terms to the y terms and the constants to the constants.\r<BR>\n" );
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document.write( "so 2x+2x=4x--->y+(-y)=0 and 18+22=40\r<BR>\n" );
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document.write( "so your left with 4x=40 or x=10\r<BR>\n" );
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document.write( "now plug x's value back into either of the original equations to find y\r<BR>\n" );
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document.write( "I choose the 1st  2(10)+y=18  subtract 20 from either side and you get y=-2 </SPAN>\n" );
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