document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23613>Question 23613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimiter of a retangle is 96. The length of the retangle is 6 less then twice the width. find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12386 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be \"w\".<BR>\n" );
document.write( "Then length = 2w-6<BR>\n" );
document.write( "Perimeter = 2l + 2w = 96<BR>\n" );
document.write( "  l + w = 48<BR>\n" );
document.write( "(2w-6) + w = 48<BR>\n" );
document.write( " 3w = 54<BR>\n" );
document.write( "  w = 18 (this is the width)<BR>\n" );
document.write( "l=2w-6= 30 (this is the length)\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );