document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23613>Question 23613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimiter of a retangle is 96. The length of the retangle is 6 less then twice the width. find the dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12385 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = 2x-6<BR>\n" );
document.write( "Width = x\r<BR>\n" );
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document.write( "Formula 2(L+W)=P\r<BR>\n" );
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document.write( "2(x+2x-6)=96<BR>\n" );
document.write( "6x-12=96<BR>\n" );
document.write( "6x=108 Divide both sides by 6 to get<BR>\n" );
document.write( "x= 18\r<BR>\n" );
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document.write( "Length = 2(18)-6=30\r<BR>\n" );
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document.write( "Hence, the width of the rectangle is 18cm and the length is 30cm.  </SPAN>\n" );
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