document.write( "Question 168020: Help!
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document.write( "Is the equation Pressure=force/area a joint variation? How do you know? \n" );
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Algebra.Com's Answer #123844 by gonzo(654) ![]() You can put this solution on YOUR website! an excerpt from the web: \n" ); document.write( "----- \n" ); document.write( "When we say z is jointly proportional to a set of variables, it means that z is directly proportional to each variable taken one at a time. \n" ); document.write( "If z varies jointly with respect to x and y, the equation will be of the form z = kxy (where k is a constant). \n" ); document.write( "Equation: c = 5ab \n" ); document.write( "Variable c is jointly proportional to a and b. That means c is directly proportional to both a and b. \n" ); document.write( "Doubling a causes c to double. Doubling b causes c to double. Doubling both a and b causes c to quadruple. \n" ); document.write( "----- \n" ); document.write( "end of excerpt. \n" ); document.write( "----- \n" ); document.write( "based on that definition, the equation as stated would not be joint. \n" ); document.write( "however, if you move the equation around, then that moved around equation could be considered joint. \n" ); document.write( "----- \n" ); document.write( "your equation p = f/a does not fit the form of a joint equation, but it can be changed to read: \n" ); document.write( "f = a*p \n" ); document.write( "f = a*p looks like it fits the form of a joint variation if you add a k into it (k = 1 in this case), i.e. f = k*a*p. \n" ); document.write( "----- \n" ); document.write( "why f = a*p would be considered joint, while p = f/a would not is beyond me, but that's what the definition states. \n" ); document.write( "----- \n" ); document.write( "the proportion has to be direct with each of 2 or more variables taken one at a time, as stated above. \n" ); document.write( "-----\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |