document.write( "Question 167993: Having some serious problems with these 3 logs:\r
\n" ); document.write( "\n" ); document.write( "1.) 2(log 2x-log y)-(log 3 + 2 log 5)\r
\n" ); document.write( "\n" ); document.write( "2.) 350/(1+e to the negative x) = 300 : solve for x (not sure where to start)\r
\n" ); document.write( "\n" ); document.write( "3.) \"the fifth\" log of (x+4) - \"the fifth\" log of x = 3 (again solving for x, but not sure where to start with this one...it just isn't working out)\r
\n" ); document.write( "\n" ); document.write( "Thanks for the help,
\n" ); document.write( "Matt G.
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Algebra.Com's Answer #123839 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
1.)
\n" ); document.write( "2(log 2x-log y)-(log 3 + 2 log 5)
\n" ); document.write( "2(log 2x-log y)-(log 3 + log 5^2)
\n" ); document.write( "2(log 2x-log y)-(log 3 + log 25)
\n" ); document.write( "2(log 2x/y)-(log 3*25)
\n" ); document.write( "log (2x/y)^2 - log 75
\n" ); document.write( "log (4x^2/y^2) - log 75
\n" ); document.write( "log (4x^2/y^2)/75
\n" ); document.write( "log (4x^2/75y^2)\r
\n" ); document.write( "\n" ); document.write( "2.) 350/(1+e to the negative x) = 300 : solve for x (not sure where to start)
\n" ); document.write( "350/(1+e^(-x)) = 300
\n" ); document.write( "350 = 300(1+e^(-x))
\n" ); document.write( "350 = 300 + 300e^(-x)
\n" ); document.write( "50 = 300e^(-x)
\n" ); document.write( "50/300 = e^(-x)
\n" ); document.write( "5/30 = e^(-x)
\n" ); document.write( "1/6 = e^(-x)
\n" ); document.write( "ln(1/6) = -x
\n" ); document.write( "-1.7918 = -x
\n" ); document.write( "1.7918 = x\r
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\n" ); document.write( "\n" ); document.write( "3.) \"the fifth\" log of (x+4) - \"the fifth\" log of x = 3
\n" ); document.write( "log5(x+4) - log5(x) = 3
\n" ); document.write( "log5[(x+4)/x] = 3
\n" ); document.write( "(x+4)/x = 5^3
\n" ); document.write( "(x+4)/x = 125
\n" ); document.write( "x+4 = 125x
\n" ); document.write( "4 = 124x
\n" ); document.write( "0.032 = x\r
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