document.write( "Question 23599: 2 horses are 10 km. apart and start moving towards each other, 1 horse @ 5.5km the other @ 4.5km. A horsefly moving @30km goes back and forth between them.
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document.write( "Question \"How far will the horsefly travel when the horses meet?\" \n" );
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Algebra.Com's Answer #12382 by stanbon(75887) ![]() You can put this solution on YOUR website! 1st find the time required for the horses to meet. \n" ); document.write( "Let distance traveled by the 5.5 km horse be \"x\". \n" ); document.write( "Then distance traveled by the 4.5 km horse will be \n" ); document.write( "\"10-x\" \n" ); document.write( "Formula: time = distance/rate \n" ); document.write( "EQUATION: \n" ); document.write( " Time for 5.5 horse = Time for 4.5 horse. \n" ); document.write( " x/5.5 = (10-x)/4.5 \n" ); document.write( " 4.5x = 55-5.5x \n" ); document.write( " 10x = 55 \n" ); document.write( " x = 11 km (distance for 5.5 km horse \n" ); document.write( "So, time for 5.5 km horse is 11/5.5 = 2 hr. \n" ); document.write( "In two hours the horsefly will go 60 km.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "So \n" ); document.write( " |