document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167924>Question 167924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 600. The lenght of the rectangle is 2 more than 3 times the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123788 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     the perimeter of a rectangle is 600. The lenght of the rectangle is 2 more than 3 times the width.<BR>\n" );
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document.write( "Let w = width of rectangle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3w+2 = length of rectangle<BR>\n" );
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document.write( "perimeter = 2(width+length)<BR>\n" );
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document.write( "600 = 2(w + 3w+2)<BR>\n" );
document.write( "300 = w + 3w+2<BR>\n" );
document.write( "300 = 4w+2<BR>\n" );
document.write( "298 = 4w<BR>\n" );
document.write( "74.5 = w (width)<BR>\n" );
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document.write( "length:<BR>\n" );
document.write( "3w+2 = 3(74.5)+2 = 223.5+2 = 225.5 (length)<BR>\n" );
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