document.write( "Question 167816: Mixing investments. Helen invested $40,000 and received a total of $ 2300 in interest after one year. If part of the money returned 5% and the remainder 8%, then how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #123716 by nerdybill(7384)\"\" \"About 
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Mixing investments. Helen invested $40,000 and received a total of $ 2300 in interest after one year. If part of the money returned 5% and the remainder 8%, then how much did she invest at each rate?
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\n" ); document.write( "Let x = amount invested at 5%
\n" ); document.write( "then
\n" ); document.write( "40000-x = amount invested at 8%
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\n" ); document.write( "Because we were given the total interest earned:
\n" ); document.write( "2300 = .05x + .08(40000-x)
\n" ); document.write( "2300 = .05x + 3200 - .08x
\n" ); document.write( "2300 = 3200 - .03x
\n" ); document.write( "2300 + .03x = 3200
\n" ); document.write( ".03x = 900
\n" ); document.write( "x = $30,000 (invested at 5%)
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\n" ); document.write( "Amount invested at 8%:
\n" ); document.write( "40000-x = 40000-30000 = $10,000 (invested at 8%)
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