document.write( "Question 167816: Mixing investments. Helen invested $40,000 and received a total of $ 2300 in interest after one year. If part of the money returned 5% and the remainder 8%, then how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #123716 by nerdybill(7384) You can put this solution on YOUR website! Mixing investments. Helen invested $40,000 and received a total of $ 2300 in interest after one year. If part of the money returned 5% and the remainder 8%, then how much did she invest at each rate? \n" ); document.write( ". \n" ); document.write( "Let x = amount invested at 5% \n" ); document.write( "then \n" ); document.write( "40000-x = amount invested at 8% \n" ); document.write( ". \n" ); document.write( "Because we were given the total interest earned: \n" ); document.write( "2300 = .05x + .08(40000-x) \n" ); document.write( "2300 = .05x + 3200 - .08x \n" ); document.write( "2300 = 3200 - .03x \n" ); document.write( "2300 + .03x = 3200 \n" ); document.write( ".03x = 900 \n" ); document.write( "x = $30,000 (invested at 5%) \n" ); document.write( ". \n" ); document.write( "Amount invested at 8%: \n" ); document.write( "40000-x = 40000-30000 = $10,000 (invested at 8%) \n" ); document.write( " \n" ); document.write( " |