document.write( "Question 167806This question is from textbook Mathematics for Edexcel IGCSE
\n" ); document.write( ": Hi thanks a lot for offering to help this is great.
\n" ); document.write( "The question gives me a rectangle with a height of 2x-1 and a width (base) of 3x-1. The question also says the length of a diagonal in the rectangle is the square root of 5. Calculate the area of the rectangle.
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Algebra.Com's Answer #123711 by KnightOwlTutor(293)\"\" \"About 
You can put this solution on YOUR website!
Since you are dealing with right triangles use the Pythagorean Theorem.\r
\n" ); document.write( "\n" ); document.write( "a^2+b^2=c^2\r
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\n" ); document.write( "\n" ); document.write( "side a=height of rectangle=2x-1
\n" ); document.write( "side b=width of rectangle=3x-1
\n" ); document.write( "Hypotenuse=diagonal =sq rt 5\r
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\n" ); document.write( "\n" ); document.write( "Plug in\r
\n" ); document.write( "\n" ); document.write( "(2x-1)^2+(3x-1)^2=5\r
\n" ); document.write( "\n" ); document.write( "Use the foil method to expand the expression.\r
\n" ); document.write( "\n" ); document.write( "4x^2-4x+1+9x^2-6x+1=5\r
\n" ); document.write( "\n" ); document.write( "Combine like terms to simplify\r
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\n" ); document.write( "\n" ); document.write( "13x^2-10x+2=5\r
\n" ); document.write( "\n" ); document.write( "Subtract 5 from both sides\r
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\n" ); document.write( "\n" ); document.write( "13x^2-10x-3=0\r
\n" ); document.write( "\n" ); document.write( "Factor\r
\n" ); document.write( "\n" ); document.write( "(13x+3)(x-1)=0\r
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\n" ); document.write( "\n" ); document.write( "x=-13/3 or 1
\n" ); document.write( "x cannot be a negative number so the only answer is x=1\r
\n" ); document.write( "\n" ); document.write( "side a=height of rectangle=2x-1=2-1=1
\n" ); document.write( "side b=width of rectangle=3x-1=3-1=2\r
\n" ); document.write( "\n" ); document.write( "area of a rectangle is axb=2\r
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