document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23587>Question 23587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^2+25<10x I need some help on this one also. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12369 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12369\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+25<10x <BR>\n" );
document.write( "x^2+25-10x <0<BR>\n" );
document.write( "(X)^2+(5)^2-2*(X)*(5)<0<BR>\n" );
document.write( "(X-5)^2<0<BR>\n" );
document.write( "A PERFECT SQUARE IS ALWAYS POSITIVE.ITS MINIMUM VALUE IS 0.IT CAN BE NEVER NEGATIVE OR LESS THAN ZERO..HENCE THIS PROBLEM HAS NO SOLUTION </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );