document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167780>Question 167780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this? This is what I have so far. <BR>\n" );
document.write( "log5(x+3)+log5(x-3)=3<BR>\n" );
document.write( "log5{(x+3)(x-3)}=3<BR>\n" );
document.write( "(x+3)(x-3)=3^5<BR>\n" );
document.write( "x^2-9=243\r<BR>\n" );
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document.write( "How do I finish this?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123677 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this? This is what I have so far. <BR>\n" );
document.write( "log5(x+3)+log5(x-3)=3<BR>\n" );
document.write( "log5{(x+3)(x-3)}=3<BR>\n" );
document.write( "(x+3)(x-3)=3^5   It's the base to the exponent.<BR>\n" );
document.write( "x^2-9=243 <BR>\n" );
document.write( "How do I finish this? <BR>\n" );
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document.write( "log5(x+3)+log5(x-3)=3 I assume this is where you started.<BR>\n" );
document.write( "Raise 5 to the power of each term.  The 2 terms added are multiplied, since the logs are added.<BR>\n" );
document.write( "(x-3)*(x+3) = 5^3 = 125<BR>\n" );
document.write( "x^2-9 = 125<BR>\n" );
document.write( "x^2 = 134<BR>\n" );
document.write( "x = ± sqrt(134) = apx ± 11.576\r<BR>\n" );
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