document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167720>Question 167720</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a natural food store makes its own brand of trial mix, out of dried apples,raisins and peanuts. One pound of the mixture is $3.18 it contains twice as much peanuts by weight than apples. One pound of dried apples cost $4.48, a pound of raisins cost $2.40 and a pound of peanuts is $ 3.44. How many ounces of each ingredient are contained in one pound of the trail mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123649 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> dried apples,raisins and peanuts. One pound of the mixture is $3.18<BR>\n" );
document.write( " it contains  twice as much peanuts by weight than apples. <BR>\n" );
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document.write( "One pound of dried apples cost $4.48, a pound of raisins cost $2.40 and <BR>\n" );
document.write( "a pound of peanuts is $ 3.44. <BR>\n" );
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document.write( "How many ounces of each ingredient are contained in one pound of the trail mix?<BR>\n" );
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document.write( "Here it is, step-by-step<BR>\n" );
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document.write( "Let a = no. of oz of apples<BR>\n" );
document.write( "Let r = no. of oz of raisins<BR>\n" );
document.write( "Let p = no. of oz of peanuts<BR>\n" );
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document.write( "The equation:<BR>\n" );
document.write( "4.48a + 2.40r + 3.44p = 3.18(16)<BR>\n" );
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document.write( "It says p = 2a, substitute 2a for p<BR>\n" );
document.write( "4.48a + 2.40r + 3.44(2a) = 3.18(16)<BR>\n" );
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document.write( "4.48a + 2.40r + 6.88a = 50.88<BR>\n" );
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document.write( "4.48a + 6.88a + 2.40r = 50.88<BR>\n" );
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document.write( "11.36a + 2.40r = 50.88<BR>\n" );
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document.write( "At this point we can say: r = (16-3a), a represents apples & peanuts here.<BR>\n" );
document.write( " Substitute (16-3a) for r, solve for a;<BR>\n" );
document.write( "11.36a + 2.40(16-3a) = 50.88<BR>\n" );
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document.write( "11.36a + 38.40 - 7.2a = 50.88<BR>\n" );
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document.write( "11.36a - 7.2a = 50.88 - 38.40<BR>\n" );
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document.write( "4.16a = 12.48<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12.48%2F4.16 ALIGN=MIDDLE  ALT=\"12.48%2F4.16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 3 oz dried apples<BR>\n" );
document.write( "then<BR>\n" );
document.write( "P = 2(3)<BR>\n" );
document.write( "P = 6 oz of peanuts<BR>\n" );
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document.write( "Find r:<BR>\n" );
document.write( "r = 16 - 3 - 6<BR>\n" );
document.write( "r = 7 oz of raisins<BR>\n" );
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document.write( "Check these values for a, r, p in the cost equation<BR>\n" );
document.write( "4.48(3) + 2.40(7) + 3.44(6) = 3.18(16)<BR>\n" );
document.write( "13.44 + 16.8 + 20.64 = 50.88; confirms our solutions </SPAN>\n" );
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