document.write( "Question 167585: For f(x) = x2-5 and g(x) = sq rt of x, find h(x)=(fg)(x)
\n" ); document.write( "I get sq rt of x2-5. Is this correct?
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Algebra.Com's Answer #123604 by midwood_trail(310)\"\" \"About 
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Given f(x) = x^2 - 5 and g(x) = sqrt{x}, find h(x) = f(g(x)).\r
\n" ); document.write( "\n" ); document.write( "We plug the value of g(x) into f(x) and simplify, if possible.\r
\n" ); document.write( "\n" ); document.write( "By doing this, we will find h(x).\r
\n" ); document.write( "\n" ); document.write( "f(sqrt{x}) = (sqrt{x})^2 - 5\r
\n" ); document.write( "\n" ); document.write( "f(sqrt{x}) = x - 5\r
\n" ); document.write( "\n" ); document.write( "So, then h(x) = x - 5\r
\n" ); document.write( "\n" ); document.write( "Did you follow?
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