document.write( "Question 167692This question is from textbook Algebra structure and method
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document.write( ": sam has 30 nickles and dimes worth $2.40. How many nickles does he have? \n" );
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Algebra.Com's Answer #123589 by nerdybill(7384) You can put this solution on YOUR website! sam has 30 nickles and dimes worth $2.40. How many nickles does he have? \n" ); document.write( ". \n" ); document.write( "Let n = nickles \n" ); document.write( "and d = dimes \n" ); document.write( ". \n" ); document.write( "We have two unknowns, so we'll need two equations: \n" ); document.write( ". \n" ); document.write( "From: \"sam has 30 nickles and dimes\" we get equation 1: \n" ); document.write( "n+d = 30 \n" ); document.write( ". \n" ); document.write( "From: \"worth $2.40\" we get equation 2: \n" ); document.write( ".05n + .10d = 2.40 \n" ); document.write( ". \n" ); document.write( "Using \"elimination method\": \n" ); document.write( "n+d = 30 \n" ); document.write( ".05n + .10d = 2.40 \n" ); document.write( ". \n" ); document.write( "multiply the top equation by -.05: \n" ); document.write( "-.05n - .05d = -1.5 \n" ); document.write( " .05n + .10d = 2.40 \n" ); document.write( ". \n" ); document.write( "Add the two equations together: \n" ); document.write( "-.05n - .05d = -1.5 \n" ); document.write( " .05n + .10d = 2.40 \n" ); document.write( "------------------------ \n" ); document.write( ".05d = .9 \n" ); document.write( "d = 18 (number of dimes) \n" ); document.write( ". \n" ); document.write( "Substitute the above into equation 1 to find n: \n" ); document.write( "n+d = 30 \n" ); document.write( "n+18 = 30 \n" ); document.write( "n = 30-18 \n" ); document.write( "n = 12 (number of nickles) \n" ); document.write( " |