document.write( "Question 167686This question is from textbook ELEMENTARY AND INTERMEDIATE ALGEBRA
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document.write( ": Brenda and her husband Randy bicycled cross-country
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document.write( "together. One morning, Brenda rode 30 miles. By traveling
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document.write( "only 5 miles per hour faster and putting in one more hour,
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document.write( "Randy covered twice the distance Brenda covered. What
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document.write( "was the speed of each cyclist? \n" );
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Algebra.Com's Answer #123584 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! i get two possibilities. \n" ); document.write( "----- \n" ); document.write( "let t = time \n" ); document.write( "let r = rate \n" ); document.write( "----- \n" ); document.write( "t*r = 30 (equation 1) \n" ); document.write( "this equation is for brenda. \n" ); document.write( "----- \n" ); document.write( "(t+1)*(r+5) = 60 (equation 2) \n" ); document.write( "this equation is for randy. he rode 1 extra hour and traveled 5 miles per hour faster than brenda. \n" ); document.write( "----- \n" ); document.write( "it t*r = 30, then r = 30/t \n" ); document.write( "substituting 30/t for r in equation 2 gets: \n" ); document.write( "(t+1)*((30/t)+5) = 60 \n" ); document.write( "----- \n" ); document.write( "multiply both sides of equation by t: \n" ); document.write( "t*(t+1)*((30/t)+5) = 60*t \n" ); document.write( "this is the same as: \n" ); document.write( "t*((30/t)+5)*(t+1) = 60*t \n" ); document.write( "this becomes: \n" ); document.write( "(30+5*t)*(t+1) = 60*t \n" ); document.write( "this becomes: \n" ); document.write( "30*t + 30 + 5*t^2 + 5*t = 60*t \n" ); document.write( "this becomes: \n" ); document.write( "35*t + 30 + 5*t^2 = 60*t \n" ); document.write( "subtract 60*t from both sides of equation: \n" ); document.write( "-25*t + 30 + 5*t^2 = 0 \n" ); document.write( "divide both sides of equation by 5: \n" ); document.write( "-5*t + 6 + t^2 = 0 \n" ); document.write( "this is the same as: \n" ); document.write( "t^2 - 5*t + 6 = 0 \n" ); document.write( "factor left side of equation: \n" ); document.write( "(t-3)*(t+2) = 0 \n" ); document.write( "t = 3 \n" ); document.write( "or \n" ); document.write( "t = -2 \n" ); document.write( "----- \n" ); document.write( "since t can't be negative, answer appears to be t = 3. \n" ); document.write( "if t = 3, then r = 10, since r*3 = 30 becomes r = 10. \n" ); document.write( "----- \n" ); document.write( "substituting t = 3 and r = 10 in equation 1: \n" ); document.write( "r*t=30 \n" ); document.write( "10*3=30 \n" ); document.write( "30=30 \n" ); document.write( "ok \n" ); document.write( "substituting t = 3 and r = 10 in equation 2: \n" ); document.write( "(t+1)*(r+5)=60 \n" ); document.write( "(3+1)*(10+5)=60 \n" ); document.write( "(4)*(15)=60 \n" ); document.write( "60=60 \n" ); document.write( "ok \n" ); document.write( "----- \n" ); document.write( "answer is: \n" ); document.write( "t = 3 while r = 10 \n" ); document.write( "Brenda traveled 10 mph for 3 hours to make 30 miles. \n" ); document.write( "Randy traveled 15 mph for 4 hours to make 60 miles. \n" ); document.write( "-----\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |