document.write( "Question 167667: factor completely
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Algebra.Com's Answer #123573 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"8a%5E2%2B4a-14ab-7b\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%288a%5E2%2B4a%29%2B%28-14ab-7b%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"4a%282a%2B1%29-7b%282a%2B1%29\" Factor out the GCF \"4a\" out of the first group. Factor out the GCF \"-7b\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%284a-7b%29%282a%2B1%29\" Since we have the common term \"2a%2B1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"8a%5E2%2B4a-14ab-7b\" factors to \"%284a-7b%29%282a%2B1%29\"
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