document.write( "Question 167652: a motorboat heads upstream for a distance of 24 miles on the Illinois River, whose current is running at 3mph. the trip up and back takes a total of 6 hours. assuming that the boat maintained a constant speed relative to the water, what is this constant speed? -- i've never been great at calculus word problems, thank u for all the help. \n" ); document.write( "
Algebra.Com's Answer #123552 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Downstream:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance-rate-time formula\r
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\n" ); document.write( "\n" ); document.write( "\"24=rt\" Plug in d=24\r
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\n" ); document.write( "\n" ); document.write( "\"24=%28r%2B3%29t\" Replace \"r\" with \"r%2B3\" (since the speed of the river sped up the boat 3 mph)\r
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\n" ); document.write( "\n" ); document.write( "\"t=24%2F%28r%2B3%29\" Divide both sides by \"r%2B3\" and rearrange to isolate \"t\"\r
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\n" ); document.write( "\n" ); document.write( "So the time it took to go downstream was \"t=24%2F%28r%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Upstream:\r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\" Start with the distance-rate-time formula\r
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\n" ); document.write( "\n" ); document.write( "\"24=rt\" Plug in d=24\r
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\n" ); document.write( "\n" ); document.write( "\"24=%28r-3%29t\" Replace \"r\" with \"r-3\" (since the speed of the river slowed the boat 3 mph)\r
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\n" ); document.write( "\n" ); document.write( "\"t=24%2F%28r-3%29\" Divide both sides by \"r-3\" and rearrange to isolate \"t\"\r
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\n" ); document.write( "\n" ); document.write( "So the time it took to go upstream was \"t=24%2F%28r-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now simply add the two times and set them equal to the total time (6 hours) to get\r
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\n" ); document.write( "\n" ); document.write( "Downstream Time + Upstream Time = Total Time\r
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\n" ); document.write( "\n" ); document.write( "\"24%2F%28r%2B3%29%2B24%2F%28r-3%29=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"24%2F%28r%2B3%29%2B24%2F%28r-3%29=6\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( " Multiply EVERY term by the LCD \"%28r%2B3%29%28r-3%29\" to clear the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"24%28r-3%29%2B24%28r%2B3%29=6%28r%2B3%29%28r-3%29\" Multiply and simplify\r
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\n" ); document.write( "\n" ); document.write( "\"24%28r-3%29%2B24%28r%2B3%29=6%28r%5E2-9%29\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"24r-72%2B24r%2B72=6r%5E2-54\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"48r=6r%5E2-54\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"0=6r%5E2-54-48r\" Subtract 48r from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"0=6r%5E2-48r-54\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ar%5E2%2Bbr%2Bc\" where \"a=6\", \"b=-48\", and \"c=-54\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for r\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28-%28-48%29+%2B-+sqrt%28+%28-48%29%5E2-4%286%29%28-54%29+%29%29%2F%282%286%29%29\" Plug in \"a=6\", \"b=-48\", and \"c=-54\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+%28-48%29%5E2-4%286%29%28-54%29+%29%29%2F%282%286%29%29\" Negate \"-48\" to get \"48\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+2304-4%286%29%28-54%29+%29%29%2F%282%286%29%29\" Square \"-48\" to get \"2304\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+2304--1296+%29%29%2F%282%286%29%29\" Multiply \"4%286%29%28-54%29\" to get \"-1296\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+2304%2B1296+%29%29%2F%282%286%29%29\" Rewrite \"sqrt%282304--1296%29\" as \"sqrt%282304%2B1296%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+3600+%29%29%2F%282%286%29%29\" Add \"2304\" to \"1296\" to get \"3600\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+sqrt%28+3600+%29%29%2F%2812%29\" Multiply \"2\" and \"6\" to get \"12\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B-+60%29%2F%2812%29\" Take the square root of \"3600\" to get \"60\". \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%2848+%2B+60%29%2F%2812%29\" or \"r+=+%2848+-+60%29%2F%2812%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+%28108%29%2F%2812%29\" or \"r+=++%28-12%29%2F%2812%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"r+=+9\" or \"r+=+-1\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"r+=+9\" or \"r+=+-1\" \r
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\n" ); document.write( "\n" ); document.write( "However, a negative speed doesn't make much sense. So the only answer is \"r+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"r+=+9\" which means that the boat was going 9 mph relative to the water. \r
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\n" ); document.write( "\n" ); document.write( "In other words, the speed of the boat in still water is 9 mph.
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