document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167595>Question 167595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1       - 1    = 6<BR>\n" );
document.write( "1+x     3 - x    35\r<BR>\n" );
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document.write( "Question reads: 1 over 1 + (plus) X - (minus) 1 over 3 - (minus) X = (EQUALS) 6 OVER 35 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123489 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Question reads: 1 over 1 + (plus) X - (minus) 1 over 3 - (minus) X = (EQUALS) 6 OVER 35<BR>\n" );
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document.write( "1/(1+x) - 1/(3-x) = 6/35\r<BR>\n" );
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document.write( "lcm = 35(1+x)(3-x)\r<BR>\n" );
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document.write( "Multiply thru by the lcm to get:\r<BR>\n" );
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document.write( "35(3-x) - 35(1+x) = (1+x)(3-x)\r<BR>\n" );
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document.write( "105-35x -35 -35x = 3 +2x -x^2\r<BR>\n" );
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document.write( "x^2 -72x + 102 = 0\r<BR>\n" );
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document.write( "x = [72 +- sqrt(72^2-4*102)]/2\r<BR>\n" );
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document.write( "x = [72 +- 69.1086..]/2\r<BR>\n" );
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document.write( "x = 1.4456... x = 70.554...<BR>\n" );
document.write( "=============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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