document.write( "Question 167583: Suppose that the width of a rectangle is 2 inches shorter than the length and that the perimeter of the rectangle is 80.
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Algebra.Com's Answer #123487 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Remember: $\"P%5BR%5D=2%28L%2BW%29\"$ , WORKING EQN
\n" ); document.write( "But, $\"W=L-2in\"$ , EQN 1
\n" ); document.write( "Subst, EQN 1 in our WORKING EQN:
\n" ); document.write( " $\"P%5BR%5D=2%28L%2BL-2%29\"$
\n" ); document.write( " $\"P%5BR%5D=2%282L-2%29\"$
\n" ); document.write( " $\"80=4L-4\"$
\n" ); document.write( " $\"80%2B4=4L\"$ -------> $\"cross%284%29L%2Fcross%284%29=cross%2884%2921%2Fcross%284%29\"$
\n" ); document.write( " $\"highlight%28L=21in%29\"$
\n" ); document.write( "Via EQN 1,
\n" ); document.write( " $\"W=21-2=highlight%2819in=W%29\"$
\n" ); document.write( "check Via WORKING EQN:
\n" ); document.write( " $\"80in=2%2821%2B19%29\"$
\n" ); document.write( " $\"80in=2%2840%29\"$
\n" ); document.write( " $\"80in=80in\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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