document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164169>Question 164169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-4= -2/3(y-9) solve for y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123470 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-4= -2/3(y-9) solve for y<BR>\n" );
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document.write( "y can be \"solved for\" only in the sense that it is expressed in terms of the other variable(s).<BR>\n" );
document.write( "That means getting y on one side of the = by itself.<BR>\n" );
document.write( "x-4= -2/3(y-9)<BR>\n" );
document.write( "Assuming you mean (-2/3)*(y-9)<BR>\n" );
document.write( "3x-12 = -2y + 18<BR>\n" );
document.write( "-2y = 3x-30<BR>\n" );
document.write( "y = -(3/2)x + 15\r<BR>\n" );
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