document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167440>Question 167440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An advertisement for an orang drink claims that the drink contains 10% orange<BR>\n" );
document.write( "juice. How much pure orange juice would have to<BR>\n" );
document.write( "be added to 5 quarts of the drink to obtain a<BR>\n" );
document.write( "mixture containing 40% orange juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123446 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lex x=amount of pure orange juice that needs to be added<BR>\n" );
document.write( "Now we know that the amount of pure orange juice in the 5 qts (0.10*5) plus the amount of pure orange juice added (x) has to equal the amount of pure orange juice in the final mixture (0.40(5+x)), so our equation to solve is:<BR>\n" );
document.write( "0.10*5+x=0.40(5+x)  get rid of parens and simplify<BR>\n" );
document.write( "0.5+x=2+0.4x  subtract 0.4x and also 0.5 from each side<BR>\n" );
document.write( "0.5-0.5+x-0.4x=2-0.5+0.4x-0.4x  collect like terms<BR>\n" );
document.write( "0.60x=1.5  divide each side by 0.6<BR>\n" );
document.write( "x=2.5 qts-----------------------------amount of pure orange juice needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.10*5+2.5=0.40(5+2.5)<BR>\n" );
document.write( "0.5+2.5=2+1<BR>\n" );
document.write( "3=3\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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