document.write( "Question 167543: solve by elimination method:
\n" ); document.write( "0.3x-0.2y=4
\n" ); document.write( "0.4x+0.3y=73/19
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Algebra.Com's Answer #123439 by sowmya(32)\"\" \"About 
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solve by elimination method:
\n" ); document.write( "0.3x-0.2y=4
\n" ); document.write( "0.4x+0.3y=73/19\r
\n" ); document.write( "\n" ); document.write( "eq 1:
\n" ); document.write( "3x-2y = 40\r
\n" ); document.write( "\n" ); document.write( "eq 2:
\n" ); document.write( "4x-3y = 730/19\r
\n" ); document.write( "\n" ); document.write( "from eq 1
\n" ); document.write( "x = (40+2y)/3\r
\n" ); document.write( "\n" ); document.write( "sub. in eq2,
\n" ); document.write( "4(40+2y)/3 -3y =730/19
\n" ); document.write( "(160+8y)/3 - 3y = 730/19
\n" ); document.write( "160+8y - 9y = 2190/19
\n" ); document.write( "y = 160-2190/19
\n" ); document.write( " =3040-2190 /19
\n" ); document.write( "y =850/19\r
\n" ); document.write( "\n" ); document.write( "x = 2460/57\r
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