document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167448>Question 167448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3x+1)(x-1)= -3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123397 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3x+1)(x-1)= -3x\r<BR>\n" );
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document.write( "Start by multiplying both factors on the left side using FOIL.\r<BR>\n" );
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document.write( "3x^2 - 3x + x - 1 = -3x\r<BR>\n" );
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document.write( "3x^2 -2x - 1 + 3x = 0\r<BR>\n" );
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document.write( "3x^2 + x - 1 = 0\r<BR>\n" );
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document.write( "Use the quadratic formula to factor and find x.\r<BR>\n" );
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document.write( "Can you take it from here?\r<BR>\n" );
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