document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167500>Question 167500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> {2x+y=16<BR>\n" );
document.write( "{3(x+y)=5x\r<BR>\n" );
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document.write( "how do i make those equations as one age word problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123383 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of two times Pauls age and Mike's age is 16 . Three times the sum of both of their ages is the same as five times Paul's age.\r<BR>\n" );
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document.write( "2x+y=16<BR>\n" );
document.write( "{3(x+y)=5x <BR>\n" );
document.write( "3x+3y=5x--->-2x+3y=0<BR>\n" );
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document.write( "add the 2 equations and the x terms are eliminated<BR>\n" );
document.write( "so we have 4y=16---->y=4  so mike is 4<BR>\n" );
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document.write( "to find Pauls age plug into either equation.. 2x+4=16----->2x=12---->x=6 which would be pauls age\r<BR>\n" );
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