document.write( "Question 167479: Hello, i was given a problem by my teacher and did not understand it:\r
\n" ); document.write( "\n" ); document.write( "When 0.5 cm was planed off of each of the 6 faces of a wooden cube its volume decreased by 169 cm^2. Find its new volume. \r
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Algebra.Com's Answer #123368 by nerdybill(7384)\"\" \"About 
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When 0.5 cm was planed off of each of the 6 faces of a wooden cube its voume decreased by 169 cm^2. Find its new volume.
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\n" ); document.write( "A \"cube\" implies that all edges are the same length.
\n" ); document.write( "Volume of a cube is \"length of an edge\" cubed.
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\n" ); document.write( "Let x = original length of one edge
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\n" ); document.write( "x-1 = edge of new cube
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\n" ); document.write( "x^3 - 169 = (x-1)^3
\n" ); document.write( "x^3 - 169 = (x-1)(x-1)(x-1)
\n" ); document.write( "x^3 - 169 = (x^2-2x+1)(x-1)
\n" ); document.write( "x^3 - 169 = (x)(x^2-2x+1)-(x^2-2x+1)
\n" ); document.write( "x^3 - 169 = (x^3-2x^2+x)-(x^2-2x+1)
\n" ); document.write( "x^3 - 169 = x^3-2x^2+x-x^2+2x-1
\n" ); document.write( "x^3 - 169 = x^3-3x^2+x+2x-1
\n" ); document.write( "x^3 - 169 = x^3-3x^2+3x-1
\n" ); document.write( "-169 = -3x^2+3x-1
\n" ); document.write( "0 = -3x^2+3x+168
\n" ); document.write( "dividing both sides by 3:
\n" ); document.write( "0 = -x^2+x+56
\n" ); document.write( "0 = x^2-x-56
\n" ); document.write( "0 = (x-8)(x+7)
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\n" ); document.write( "x = {-7, 8}
\n" ); document.write( "We can toss out the negative solution so we end up with:
\n" ); document.write( "x = 8 cm (length of an edge of the original cube)
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\n" ); document.write( "Length of new cube edge:
\n" ); document.write( "x-1 = 8-1 = 7 cm
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\n" ); document.write( "Finally, volume of new cube is:
\n" ); document.write( "7^3 = 343 cubic cm\r
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