document.write( "Question 167421: If Train A & Train B are traveling the same direction on parallel tracks. Train A is going 60 MPH, Train B is going 80 MPH. Train A passes a station at 12:20 PM. If Train B passes the same station at 12:32 PM, what time will Train B catch up to Train A? \n" ); document.write( "
Algebra.Com's Answer #123332 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "We are basically told that Train B is 12 min behind Train A.\r
\n" ); document.write( "\n" ); document.write( "Let t=amount of time needed for Train B to catch up with Train A after Train B passes the station\r
\n" ); document.write( "\n" ); document.write( "Distance train A has travelled from the station when Train B catches up=60*(12/60)+60t
\n" ); document.write( "Distance train B has travelled from the station when it catches Train A=80t\r
\n" ); document.write( "\n" ); document.write( "When the above two distances are equal, train B will have caught Train A, so:
\n" ); document.write( "60*(12/60)+60t=80t
\n" ); document.write( "12+60t=80t subtract 60 t from each side
\n" ); document.write( "12=80t-60t
\n" ); document.write( "20t=12 divide each side by 20
\n" ); document.write( "t=12/20=6/10=3/5 hr=36 min----time needed for Train B to catch Train A
\n" ); document.write( "Therefore, Train B catches Train A at 12:32 + 36 min=1:08 PM\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "12+60(3/5)=80(3/5)
\n" ); document.write( "12+36=3*16
\n" ); document.write( "48=48\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
\n" ); document.write( " \n" ); document.write( "
\n" );