document.write( "Question 167370: A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 part gasoline and 1 part oil?\r
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document.write( "I tried to make a chart to list everything I knew from the problem and see how I could solve it, but I'm not sure where to start from. \n" );
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Algebra.Com's Answer #123292 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of gas that needs to be added\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of oil in the 32-1 mixture is the same as the amount of oil in the 40-1 mixture (since we neither add or take away any oil); so: \n" ); document.write( "2*(1/32)=1/40(2+x) get rid of parens \n" ); document.write( "1/16=1/20 + x/40 (LCD=80) multiply each term by 80 \n" ); document.write( "5=4+2x subtract 4 from each side \n" ); document.write( "5-4=2x divide by 2 \n" ); document.write( "x=1/2 gal amount of gas that needs to be added\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "(1/32)*2=(1/40)*2.5 \n" ); document.write( "1/16=1/16\r \n" ); document.write( "\n" ); document.write( "Hope this helps------ptaylor \n" ); document.write( " |