document.write( "Question 167309: How would I write an equation with a slope of -1/3 \n" ); document.write( "
Algebra.Com's Answer #123227 by gonzo(654)\"\" \"About 
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slope intercept form of a linear equation is y = m*x + b
\n" ); document.write( "m is the slope.
\n" ); document.write( "b is the y intercept.
\n" ); document.write( "if you slope is -1/3, then the equation becomes:
\n" ); document.write( "y = -1/3*x + b
\n" ); document.write( "since you don't know anything else about the line, that's where you stop.
\n" ); document.write( "if you have a point on the line, then you can solve for b.
\n" ); document.write( "assume (1,3) is a point on the line.
\n" ); document.write( "(x,y) = (1,3)
\n" ); document.write( "x = 1
\n" ); document.write( "y = 3
\n" ); document.write( "substitute in your equation for y and x as follows:
\n" ); document.write( "y = -1/3*x + b
\n" ); document.write( "3 = (-1/3)*(1) + b
\n" ); document.write( "this becomes:
\n" ); document.write( "3 = -1/3 + b
\n" ); document.write( "adding 1/3 to both sides of the equation and it becomes:
\n" ); document.write( "3 + 1/3 = b
\n" ); document.write( "or:
\n" ); document.write( "10/3 = b
\n" ); document.write( "----
\n" ); document.write( "your equation now becomes:
\n" ); document.write( "y = -1/3x + 10/3
\n" ); document.write( "a graph of this equation looks like:
\n" ); document.write( "check below the graph for further comments.
\n" ); document.write( "\"graph%28800%2C800%2C-5%2C5%2C-5%2C5%2C-1%2F3%2Ax%2B%2810%2F3%29%29\"
\n" ); document.write( "your equation is:
\n" ); document.write( "y = -1/3x + 10/3
\n" ); document.write( "y intercept is the y value when x = 0.
\n" ); document.write( "y = 10/3 = 3 + 1/3 as you might be able to see on the graph. look for the value of y when x = 0.
\n" ); document.write( "you should also be able to see that when x = 1, y = 3.
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