document.write( "Question 167310: how do you find \"x\" in a equation like\r
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document.write( "2x-3=5x+12\r
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document.write( "??? \n" );
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Algebra.Com's Answer #123224 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! you want to get all your x's on the same side of the equation. \n" ); document.write( "you do this by any of the following: \n" ); document.write( "1. add or subtract the same value to both sides of the equation. \n" ); document.write( "2. multiply or divide each side of the equation by the same value. \n" ); document.write( "3. raise both sides of the equation by the same power. \n" ); document.write( "all of these operations, if done properly, do not change the value of the equation. \n" ); document.write( "----- \n" ); document.write( "in your problem, you start off with: \n" ); document.write( "2x-3 = 5x + 12 \n" ); document.write( "you want to move all your x's to the left side of the equation or the right side of the equation. \n" ); document.write( "let's try the right. \n" ); document.write( "you subtract 2x from both sides of the equation. \n" ); document.write( "2x - 3 - 2x = 5x - 2x + 12. \n" ); document.write( "when you combine like terms, the 2x on the left side of the equation cancels out. \n" ); document.write( "combining like terms, you get: \n" ); document.write( "-3 = 3x + 12. \n" ); document.write( "now you want to move the 12 from the right side of the equation to the left side. \n" ); document.write( "you do this by subtracting 12 from both sides of the equation. \n" ); document.write( "-3 - 12 = 3x + 12 - 12. \n" ); document.write( "when you combine like terms, the 12 on the right side of the equation cancels out. \n" ); document.write( "combine like terms, you get: \n" ); document.write( "-15 = 3x \n" ); document.write( "now you need to divide both sides of the equation by 3. \n" ); document.write( "-15 / 3 = 3x / 3 \n" ); document.write( "completing the operation, you get: \n" ); document.write( "-5 = x \n" ); document.write( "this is the same as: \n" ); document.write( "x = -5 \n" ); document.write( "that should be your answer. \n" ); document.write( "substituting -5 for x in your original equation gets: \n" ); document.write( "2x-3=5x+12 \n" ); document.write( "(2*-5) - 3 = (5*-5) + 12 \n" ); document.write( "-10 - 3 = -25 + 12 \n" ); document.write( "-13 = -13 \n" ); document.write( "since the 2 sides of the equatin are equal, the value of x = -5 is true. \n" ); document.write( "----- \n" ); document.write( " |