document.write( "Question 166790: A bicyclist rode up a mountain road at 12 km/h and then back down at 30 km/h. If the round trip toook 3.5 hours, how long did the ride up the mountain take? \n" ); document.write( "
Algebra.Com's Answer #123165 by jojo14344(1513)\"\" \"About 
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A bicyclist rode up a mountain road at 12 km/h and then back down at 30 km/h. If the round trip toook 3.5 hours, how long did the ride up the mountain take?
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\n" ); document.write( "Remember: \"Speed=Distance%2Ftime\", EQN 1
\n" ); document.write( "Given---\"S%5Bup%5D=12kph\",\"S%5Bdn%5D=30kph\";\"time=3.5hrs\"
\n" ); document.write( "*Note: \"time=t%5Bup%5D%2Bt%5Bdn%5D\", EQN 2
\n" ); document.write( "Via EQN 1, we get --> \"Distance=Speed%2Atime\"
\n" ); document.write( "Since both distance is the same, we equate both going up and down:
\n" ); document.write( "\"D%5Bup%5D=D%5Bdn%5D\"
\n" ); document.write( "\"S%5Bup%5D%2At%5Bup%5D=S%5Bdn%5D%2At%5Bdn%5D\", EQN 3
\n" ); document.write( "Via EQN 2, we get \"t%5Bdn%5D=time-t%5Bup%5D\", EQN 4 ---> subst. in EQN 3:
\n" ); document.write( "\"S%5Bup%5D%2At%5Bup%5D=S%5Bdn%5D%2A%28time-t%5Bup%5D%29\"
\n" ); document.write( "\"%2812%29%2At%5Bup%5D=%2830%29%283.5-t%5Bup%5D%29\"
\n" ); document.write( "\"12%2At%5Bup%5D=105-30t%5Bup%5D\"
\n" ); document.write( "\"12t%5Bup%5D%2B30t%5Bup%5D=105\"
\n" ); document.write( "\"42t%5Bup%5D=105\" ------> \"cross%2842%29t%5Bup%5D%2Fcross%2842%29=cross%28105%292.5%2Fcross%2842%29\"
\n" ); document.write( "\"highlight%28t%5Bup%5D=2.5hrs%29\", ANSWER in going up
\n" ); document.write( "For the record, Via EQN 2---> \"t%5Bdn%5D=3.5-2.5=1hr\", going down
\n" ); document.write( "* This just make sense, that it will take more time to go up than to go down.
\n" ); document.write( "Check Via EQN 3:
\n" ); document.write( "\"12%2A2.5=30%2A1\"
\n" ); document.write( "\"30km=30km\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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