document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23410>Question 23410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 10c2-21c=-4c+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12315 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2-21c=-4c%2B6 ALIGN=MIDDLE  ALT=\"10c%5E2-21c=-4c%2B6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Are you sure you didn't copy this one wrong?  It works out a LOT better (it factors!) if you had written this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2+-21c+=+-4c+-6 ALIGN=MIDDLE  ALT=\"10c%5E2+-21c+=+-4c+-6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  I'm going to take the liberty of changing it, and if I'm wrong, then just repost the question.  I will owe you a solution to the other problem, using the quadratic formula (or one of algebra.com quadratic equation solver!)\r<BR>\n" );
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document.write( "So I'm saying let's do this: <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2+-21c+=+-4c+-6 ALIGN=MIDDLE  ALT=\"10c%5E2+-21c+=+-4c+-6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  \r<BR>\n" );
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document.write( "This is a quadratic equation, so set it equal to zero, by adding +4c +6 to each side:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2+-21c+%2B4c+%2B6+=+-4c+%2B+6+%2B4c%2B6+ ALIGN=MIDDLE  ALT=\"10c%5E2+-21c+%2B4c+%2B6+=+-4c+%2B+6+%2B4c%2B6+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2+-17c+%2B6+=+0 ALIGN=MIDDLE  ALT=\"10c%5E2+-17c+%2B6+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This can be a tough factoring problem.  You might want to see a page on my website:  click on my tutor name \"rapaljer\" anywhere in algebra.com, and look for \"Basic Algebra\", then go to \"Samples of Basic Algebra: One Step at a Time.\"  Then in Chapter 2 there are several sections on factoring.  The one you need here for this problem is the one I call \"Advanced Trinomial Factoring.\"  It is a DETAILED explanation, with examples, exercises, and solutions to ALL the exercises-- and like everything else around here, it's ALL FREE!!\r<BR>\n" );
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document.write( "Back to the problem:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10c%5E2+-17c+%2B6+=+0 ALIGN=MIDDLE  ALT=\"10c%5E2+-17c+%2B6+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You need to find two numbers whose product is 10c^2.  Most likely that will be 5c*2c:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285c______%29%2A%282c______%29+=+0 ALIGN=MIDDLE  ALT=\"%285c______%29%2A%282c______%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, you need to find two numbers whose product is +6, and the middle term has to add up to a  -17c.  The signs will both be negative, so try -6*-1 (since I happen to have already tried the -3*-2 and it didn't work out right.  I think you should putting the -6 first and the -1 in the second slot.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285c-6%29%282c-1%29=+0 ALIGN=MIDDLE  ALT=\"%285c-6%29%282c-1%29=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you will do the OUTER times OUTER and the INNER times INNER, you will have -5c -12c, which is -17c.\r<BR>\n" );
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document.write( "Now finish the problem by separating the quadratic equation into TWO solutions:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285c-6%29%282c-1%29=+0 ALIGN=MIDDLE  ALT=\"%285c-6%29%282c-1%29=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "First solution:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5c-6=0 ALIGN=MIDDLE  ALT=\"5c-6=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5c=6 ALIGN=MIDDLE  ALT=\"5c=6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=+6%2F5 ALIGN=MIDDLE  ALT=\"c=+6%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Second solution:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2c-1=+0 ALIGN=MIDDLE  ALT=\"2c-1=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2c=1 ALIGN=MIDDLE  ALT=\"2c=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=+1%2F2 ALIGN=MIDDLE  ALT=\"c=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 at SCC  </SPAN>\n" );
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