document.write( "Question 167214: I have 27 balls. 14 are red and 13 blue. I deceded to group the balls into a group of 3s ?
\n" ); document.write( "the balls will be choosen randomly.
\n" ); document.write( "What is the probablity that the group will have 2 red and 1 blue.
\n" ); document.write( "2)-the probability that the group will have all reds or all blue \n" ); document.write( "

Algebra.Com's Answer #123147 by Edwin McCravy(20086) $\"\"$ $\"About$

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Edwin's solution:\r
\n" ); document.write( "\n" ); document.write( "I have 27 balls. 14 are red and 13 blue. I decided to group the balls into a group of 3s the balls will be choosen randomly.
\n" ); document.write( "Then one of the groups of three was chosen at random.
\n" ); document.write( "What is the probablity that the group chosen will have 2 red and 1 blue.\r
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document.write( "We can pick the two reds 14C2 ways and the one blue 13C1 ways.\r\n" );
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document.write( "So the numerator of the probability is (14C2)(13C1)  \r\n" );
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document.write( "The denominator is 27C3.\r\n" );
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document.write( "So the probability is \r\n" );
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document.write( "2)-the probability that the group will have all reds or all blue\r\n" );
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document.write( "P(all reds or all blue) = P(all reds) + P(all blue)\r\n" );
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document.write( "P(all reds) = \r\n" );
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document.write( "P(all blues) = \r\n" );
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document.write( "P(all reds or all blue) = P(all reds) + P(all blue) =\r\n" );
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document.write( " =   = .\r\n" );
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document.write( "Edwin

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