document.write( "Question 167159: The sum of two consecutive even integers is ten less than twice their product. Find their integers using factoring. \n" ); document.write( "
Algebra.Com's Answer #123121 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
The sum of two consecutive even integers is ten less than twice their product. Find their integers using factoring.
\n" ); document.write( ".
\n" ); document.write( "Let x = 1st consecutive even integers
\n" ); document.write( "then
\n" ); document.write( "x+2 = 2nd consecutive even integers
\n" ); document.write( ".
\n" ); document.write( "x + x+2 = 2(x)(x+2) -10
\n" ); document.write( "2x+2 = 2x(x+2) -10
\n" ); document.write( "2x+2 = 4x^2+4x -10
\n" ); document.write( "2 = 4x^2+2x-10
\n" ); document.write( "0 = 4x^2+2x-12
\n" ); document.write( "0 = 2x^2+x-6
\n" ); document.write( ".
\n" ); document.write( "0 = (2x-3)(x+2)
\n" ); document.write( ".
\n" ); document.write( "Setting each to zero:
\n" ); document.write( "2x-3 = 0
\n" ); document.write( "2x = 3
\n" ); document.write( "x = 3/2
\n" ); document.write( ".
\n" ); document.write( "x+2 = 0
\n" ); document.write( "x = -2
\n" ); document.write( ".
\n" ); document.write( "Solution: x = {-2, 3/2}\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );