document.write( "Question 167110: If y varies directly as the square of x, and y=7 when x=9, find y when x=7. \n" ); document.write( "
Algebra.Com's Answer #123115 by midwood_trail(310)\"\" \"About 
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If y varies directly as the square of x, and y=7 when x=9, find y when x=7.\r
\n" ); document.write( "\n" ); document.write( "y varies directly as x^2 is written y = kx^2, where k is the constant of variation.\r
\n" ); document.write( "\n" ); document.write( "y = 7 when x = 9. Given this data, we first solve for k.\r
\n" ); document.write( "\n" ); document.write( "y = kx^2\r
\n" ); document.write( "\n" ); document.write( "7 = k(9)^2\r
\n" ); document.write( "\n" ); document.write( "7 = 81k\r
\n" ); document.write( "\n" ); document.write( "7/81 = k\r
\n" ); document.write( "\n" ); document.write( "We now multiply the value just found for k by 7^2 or 49 to find y.\r
\n" ); document.write( "\n" ); document.write( "y = (7/81)(7)^2\r
\n" ); document.write( "\n" ); document.write( "y = (7/81)(49)\r
\n" ); document.write( "\n" ); document.write( "y = 343/81\r
\n" ); document.write( "\n" ); document.write( "Did you follow?\r
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