document.write( "Question 167161: A rock is thrown upward from the ground with an initial velocity of 96 feet per second. The equation giving the height above the ground is h=96t-16t^2, h is the height in feet and t is the number of seconds after the rock is thrown.\r
\n" ); document.write( "\n" ); document.write( "a. Find the number of seconds when the rock is 80 feet above the ground.
\n" ); document.write( "b. Find the number of seconds until the rock hits the ground again.
\n" ); document.write( "

Algebra.Com's Answer #123112 by midwood_trail(310)\"\" \"About 
You can put this solution on YOUR website!
To solve part (a) set equation to 80 and solve for t.\r
\n" ); document.write( "\n" ); document.write( "To solve (b), set equation to zero and solve for t.
\n" ); document.write( "
\n" );