document.write( "Question 167095This question is from textbook Amscos Integrated algebra 1
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document.write( ": Nolan walked to the store from his home at the rate of 5 miles per hour. after spending one half hour in the store,his friend gave him a ride home at the rate of 30 miles per hour. he arrived home 1 hour and 5 minutes (1 1/12) after he left. how far is the store from nolans home?\r
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Algebra.Com's Answer #123111 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! distance equals rate multiplied by time\r \n" ); document.write( "\n" ); document.write( "in this case no matter how Nolan travels the distance between home and the store is equal to the distance from the store back to home. Also total travel time is 7/12 of and hour(35 minutes). Figured as \n" ); document.write( "\n" ); document.write( "so distance from home to store is represented as d=5mph((7/12)-t)and distance from store to home is represented as d=30t\r \n" ); document.write( "\n" ); document.write( "since we know thes are equal we have 30t=(35/12)-5t\r \n" ); document.write( "\n" ); document.write( "multiply everything by 12 360t=35-60t---->420t=35---->t=35/420=1/12\r \n" ); document.write( "\n" ); document.write( "so 1/12 of and hour or 5 minutes is the time traveled from the store to home \n" ); document.write( "in the car\r \n" ); document.write( "\n" ); document.write( "which means that (7/12-1/12)= 1/2 hr or 30 minutes of travel time as Nolan walked from home to the store. \n" ); document.write( " |