document.write( "Question 23507: Hi I would like to know the formula for working out x squared = x + 6. If you can answer my question, I am very thankful. \n" ); document.write( "
Algebra.Com's Answer #12310 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
This is a quadratic equation \"x%5E2+=+x%2B6\" so you might be thinking of the quadratic formula that looks like this:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" . However, this problem just might factor, and this is MUCH easier than the quadratic formula when the problem factors!\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+x%2B6\" \r
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\n" ); document.write( "\n" ); document.write( "The first step is to set the equation equal to zero. You can either take everything to the right side or the left side, but I recommend that you arrange the terms so the \"x%5E2\" term is positive. In this case, it means to take everything to the left side. Subtract x and 6 from both sides:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+x%2B6\"
\n" ); document.write( "\"x%5E2-x+-6+=+x%2B6-x+-6\"
\n" ); document.write( "\"x%5E2+-+x+-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "This just happens to factor!
\n" ); document.write( "\"%28x-3%29%28x%2B2%29+=0\"\r
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\n" ); document.write( "\n" ); document.write( "There are TWO solutions:
\n" ); document.write( "x-3 = 0, so x= 3
\n" ); document.write( "x+2 = 0, so x=-2\r
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\n" ); document.write( "\n" ); document.write( "Final answer: x= 3 or x= -2\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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