document.write( "Question 167100This question is from textbook
\n" ); document.write( ": I want to double check to make sure that I did this problem right or did I misunderstand the question.\r
\n" ); document.write( "\n" ); document.write( "Convert the repeating decimal 0.1212...to a fraction with integer numerator and demoninator.\r
\n" ); document.write( "\n" ); document.write( "1/10 + 2/100 + 1/1000 + 2/10,000\r
\n" ); document.write( "\n" ); document.write( "(1,000 + 200 + 10 + 2)/10,000 = 1,212/10,000\r
\n" ); document.write( "\n" ); document.write( "I then divided by 2 to simplify which = 606/5000
\n" ); document.write( "\" \" = 303/2500 being the final answer\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #123078 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, nice try, but your answer of \"303%2F2500+=+0.1212\" and this is a terminating (non-repeating) decimal! You can check this in your calculator.
\n" ); document.write( "Here's the way to convert this repeating decimal to a fraction:
\n" ); document.write( "Let n = 0.1212... Multiply both sides by 100 to get:
\n" ); document.write( "100n = 12.1212... Now subtract n = 0.1212...
\n" ); document.write( "100n-n = (12.1212...)-(0.1212...) Perform the indicated subtraction.
\n" ); document.write( "99n = 12 Finally divide both sides by 99.
\n" ); document.write( "\"n+=+12%2F99\" substitute n = 0.1212...
\n" ); document.write( "0.1212... = \"12%2F99\" Reduce the fraction.
\n" ); document.write( "0.1212... = \"4%2F33\"
\n" ); document.write( "
\n" );