document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167032>Question 167032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $30 a pound that she wishes to mix with 90 pounds of coffee work $60 a pound to get a mixture that can be sold for $40 a pound.  How many pounds of the $30 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123033 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of the $30 coffee needed\r<BR>\n" );
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document.write( "($ understood)<BR>\n" );
document.write( "Now we know that the value of the $30 coffee (30x) plus the value of the $60 coffee (60*90) has to equal the value of the final mixture(40* (90+x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "30x+60*90=40(90+x)  get rid of parens and simplify<BR>\n" );
document.write( "30x+5400=3600+40x subtract 30x and also 3600 from each side<BR>\n" );
document.write( "30x-30x+5400-3600=3600-3600+40x-30x  collect like terms<BR>\n" );
document.write( "1800=10x  divide each side by 10<BR>\n" );
document.write( "x=180 lbs -------------amount of $30 coffee needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "30*180+60*90=40*270<BR>\n" );
document.write( "5400+5400=10800<BR>\n" );
document.write( "10800=10800\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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