document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166977>Question 166977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> tom caught five more fish than pete and henry caught three times as many fish as tom together they caught 50 fish how many did tom catch </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #123002 by </B><A HREF=/tutors/aboutme.mpl?userid=piglet162431><B>piglet162431(90)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=piglet162431><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=123002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK, let's start by setting x be the number of fish Pete caught<BR>\n" );
document.write( "to express the number Tom caught, we use the expression x + 5<BR>\n" );
document.write( "And for Henry, 3(x+5) because he caught 3 times as many fish as tom\r<BR>\n" );
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document.write( "all these fish add to be 50<BR>\n" );
document.write( "so x + x+5 + 3(x+5) = 50<BR>\n" );
document.write( "5x=30<BR>\n" );
document.write( "x=6\r<BR>\n" );
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document.write( "So Tom is x +5, substitute in 6 + 5 = 11<BR>\n" );
document.write( "Tom caught 11 fish. </SPAN>\n" );
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