document.write( "Question 166972: Anna made the following announcement:\r
\n" );
document.write( "\n" );
document.write( "\" In 7 years, I will be half my mother's age. Thirteen years ago, she was 6 times as old as I was then.\"
\n" );
document.write( "How old is Anna now?\r
\n" );
document.write( "\n" );
document.write( "My teacher gives us a \"problem of the week\" every week and this is it. I'm not sure how to figure out the answer. \n" );
document.write( "
Algebra.Com's Answer #122996 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Anna made the following announcement: \n" ); document.write( "\" In 7 years, I will be half my mother's age. Thirteen years ago, she was 6 times as old as I was then.\" \n" ); document.write( "How old is Anna now? \n" ); document.write( "-------------------- \n" ); document.write( "A = Anna's age \n" ); document.write( "M = Mother's age \n" ); document.write( "In 7 years, I will be half my mother's age. \n" ); document.write( "M+7 = 2*(A+7) \n" ); document.write( "-------------- \n" ); document.write( "Thirteen years ago, she was 6 times as old as I was then. \n" ); document.write( "M-13 = 6*(A-13) \n" ); document.write( "Now there are 2 eqns in 2 unknowns. \n" ); document.write( "M + 7 = 2A+14 eqn 1 \n" ); document.write( "M -13 = 6A-78 eqn 2 \n" ); document.write( "3M+21 = 6A+42 eqn 1 times 3 \n" ); document.write( "Subtract \n" ); document.write( "-2M-34= -120 \n" ); document.write( "-2M = -86 \n" ); document.write( "M = 43 (Mother's age) \n" ); document.write( "Sub into eqn 1 \n" ); document.write( "43+7 = 2A + 14 \n" ); document.write( "2A = 36 \n" ); document.write( "A = 18 (Anna's age) \n" ); document.write( "----------- \n" ); document.write( "Check: \n" ); document.write( "13 years ago, they were ages 5 and 30, = 6 times. \n" ); document.write( "In 7 years, they'll be 25 and 50, 2 times.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |