document.write( "Question 23533: Solve the System by Substitution:\r
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document.write( "y=x+4\r
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document.write( "3x+y=16 \n" );
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Algebra.Com's Answer #12299 by rapaljer(4671) You can put this solution on YOUR website! y=x+4 \n" ); document.write( "3x+y=16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the y from the first equation into the second equation:\r \n" ); document.write( "\n" ); document.write( "3x+ (_____)= 16 \n" ); document.write( "3x + (x+4) = 16 \n" ); document.write( "4x + 4 = 16 \n" ); document.write( "4x = 12 \n" ); document.write( "x=3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the x into the \"y=\" equation in order to find y:\r \n" ); document.write( "\n" ); document.write( "y=x+4 \n" ); document.write( "y = 3+ 4= 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check in the second equation: \n" ); document.write( "3x+y=16 \n" ); document.write( "3(3) + 7= 16 \n" ); document.write( "9+7=16 \n" ); document.write( "It checks!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |