document.write( "Question 166738: a pedestrian is three eights of the way across the a train bridge when he hears a train coming! If he runs as fast as possible back toward the train, he will get off just in in time to aviod a collision. Also, if he runs as fast as possible away from the train, he will get off the bridge (on the other side) just in time to aviod a collision.\r
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Algebra.Com's Answer #122969 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a pedestrian is three eights of the way across the a train bridge when he hears a train coming! If he runs as fast as possible back toward the train, he will get off just in in time to avoid a collision. Also, if he runs as fast as possible away from the train, he will get off the bridge (on the other side) just in time to avoid a collision.
\n" ); document.write( "If the train is traveling at 60 miles per hour. How fast does the person run?
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\n" ); document.write( "Train----------d------------Br.....3x......P..........5x.........Br
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\n" ); document.write( "Let d = dist train is from the bridge
\n" ); document.write( "Let 8x = length of the bridge
\n" ); document.write( "Pedestrian is 3x from one end and 5x from the other end of the bridge
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\n" ); document.write( "Let s = running speed of p (mph)
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\n" ); document.write( "Toward the train time equation (arrive at end of the bridge at the same time)
\n" ); document.write( "\"d%2F60\" = \"%283x%29%2Fs\"
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\n" ); document.write( "Away from the train time equation (arrive at other end at the same time)
\n" ); document.write( "\"%28%28d%2B8x%29%29%2F60\" = \"%285x%29%2Fs\"
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\n" ); document.write( "After much manipulation of these equations (too much, to record here) I came up with:
\n" ); document.write( "d = 7.2
\n" ); document.write( "8x = 4.8 mi
\n" ); document.write( "P = 1.8 mi from one end and 3 mi from the other end
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\n" ); document.write( "s = 15 mph running speed
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\n" ); document.write( "Check this using the \"away from the train\" situation:
\n" ); document.write( "\"%28%287.2%2B4.8%29%29%2F60\" = \"3%2F15\"
\n" ); document.write( "\"12%2F60\" = \"3%2F15\" = .2 hrs
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\n" ); document.write( "Check using the \"toward the train\" situation
\n" ); document.write( "\"7.2%2F60\" = \"1.8%2F15\" = .12 hrs\r
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