document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166877>Question 166877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve this \r<BR>\n" );
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document.write( "find the solution to each system by the substitution method?\r<BR>\n" );
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document.write( "4x + 3y= 9<BR>\n" );
document.write( "3y+6=x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122946 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve this <BR>\n" );
document.write( "find the solution to each system by the substitution method? <BR>\n" );
document.write( "4x + 3y= 9<BR>\n" );
document.write( "3y+6=x<BR>\n" );
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document.write( "Since x is shown in terms of y, sub for x in the 1st eqn.<BR>\n" );
document.write( "4x + 3y= 9<BR>\n" );
document.write( "4*(3y+6) + 3y = 9<BR>\n" );
document.write( "12y + 24 + 3y = 9<BR>\n" );
document.write( "15y = -15<BR>\n" );
document.write( "y = -1<BR>\n" );
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document.write( "Sub into either eqn:<BR>\n" );
document.write( "3*(-1) + 6 = x<BR>\n" );
document.write( "x = 3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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