document.write( "Question 166893: 3 √13/3\r
\n" ); document.write( "\n" ); document.write( "Simplify: 3 ( square root of 13 over 3)\r
\n" ); document.write( "\n" ); document.write( "This is the same question. Just wasnt sure about the best way to present it.
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Algebra.Com's Answer #122945 by MRperkins(300)\"\" \"About 
You can put this solution on YOUR website!
\"%28%283%29sqrt%2813%29%29%2F3\"
\n" ); document.write( "the 3 in the numerator (top number) reduces with the 3 in the denominator and you are left with \"%281%2Asqrt%2813%29%29%2F1\" or simply \"sqrt%2813%29\"
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\n" ); document.write( "If the problem reads \"3sqrt%2813%2F3%29\" then you will get a different answer.
\n" ); document.write( "in this case you will rewrite the fraction as the sqrt of the numerator over the sqrt of the denominator. So it would look like this: \"%283sqrt%2813%29%29%2F%28sqrt%283%29%29\"
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\n" ); document.write( "now you have 3 to the 1st power on the top and 3 to the 1/2 power on the bottom. These reduce to 3 to the 1/2 power on top and 3 to the 0 power(which is 1) on the bottom. now you can rewrite 3 to the 1/2 power as a sqrt. The formula now looks like this: \"sqrt%283%29%2Asqrt%2813%29\"
\n" ); document.write( "you can multiply these to get \"sqrt%283%2A13%29\". Since you can not pull any factors out then you should combine the terms and get: \"sqrt%2839%29\"
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\n" ); document.write( "look at both examples to make sure you see the differences. Then pick the example that matches your problem.
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\n" ); document.write( "I hope this helps!
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\n" ); document.write( "Private tutoring is available. Click on my name to go to my website or email me at justin.sheppard.tech@hotmail.com for more information. If you have any other questions you can direct them to me personally and I will answer them for you.
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