document.write( "Question 166836: A BOY USES A MOVING SIDEWALK IN AN AIRPORT. WHEN HE RUNS IN THE DIRECTION OF THE MOVING SIDEWALK HE CAN GO 303 METERS IN 3 MINUTES.WHEN HE RUNS BACK AGAINST THE MOVING SIDEWALK HE CAN ONLY GO 275 METERS IN 5 MINUTES. HOW FAST DOES THE BOY RUN WHEN THE SIDFWALK IS STILL? HOW FAST DOES THE MOVING SIDEWALK RUN? \n" ); document.write( "
Algebra.Com's Answer #122942 by Mathtut(3670)\"\" \"About 
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lets call the boys rate with the sidewalk=rw and rw=r+rs r being the rate of the boy and rs being the rate of the sidewalk\r
\n" ); document.write( "\n" ); document.write( "lets call the boys rate against the sidewalk and ra=r-rs \r
\n" ); document.write( "\n" ); document.write( "now figuring rates we have rw=303/3=101
\n" ); document.write( ": ra=275/5= 55\r
\n" ); document.write( "\n" ); document.write( "using our equations above we arrive at 101=r+rs
\n" ); document.write( ": and 55=r-rs\r
\n" ); document.write( "\n" ); document.write( "adding the 1st and 2nd equation together we arrive at 2r=156 so r=78\r
\n" ); document.write( "\n" ); document.write( "since r=78 then rs=101-78=23\r
\n" ); document.write( "\n" ); document.write( "so the rate of the boy is 78 meters per minute
\n" ); document.write( "and the rate of the sidewalk is 23 meters per minute
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