Algebra.Com's Answer #122905 by nerdybill(7384)  You can put this solution on YOUR website! log5(x^2+x+4)=2 \n" );
document.write( "x^2+x+4 = 5^2 \n" );
document.write( "x^2+x+4 = 25 \n" );
document.write( "x^2+x-21 = 0 \n" );
document.write( "Since we can't factor, we must use the quadratic equation. \n" );
document.write( "Doing so will yield: \n" );
document.write( "x = {4.110, -5.110} \n" );
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document.write( " | Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=85 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 4.10977222864644, -5.10977222864644.\n" );
document.write( "Here's your graph: \n" );
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