document.write( "Question 166704: Sarah borrowed $6000, part at 15.5% and the rest at 14.25%. At the end of 3 years and 6 months, he had paid $3150 in simple interest. How much did he borrow at each rate? \n" ); document.write( "
Algebra.Com's Answer #122896 by aswathytony(47)\"\" \"About 
You can put this solution on YOUR website!
Amount borrowed = $6000\r
\n" ); document.write( "\n" ); document.write( "if she borrowed 'x' at 15.5% , rest is 6000 - x and borrowed at 14.25%\r
\n" ); document.write( "\n" ); document.write( "simple interest = p*n*r / 100 n = 3yrs + 6m = 3+ 1/2 yrs = 7/2 yrs\r
\n" ); document.write( "\n" ); document.write( " 3150 = x * 7/2 * 15.5 /100 + (6000 - x ) * 7/2 * 14.25 /100
\n" ); document.write( " = 0.5425 x + (6000 -x) *0.4988
\n" ); document.write( " = 0.5425x + 6000 *0.4988 -0.4988x
\n" ); document.write( " = 0.0437 x + 2992.8
\n" ); document.write( "3150 -2992.8 = 0.0437 x
\n" ); document.write( " 157.2 =0.0437x
\n" ); document.write( " x = 157.2/0.0437 = 3597.25\r
\n" ); document.write( "\n" ); document.write( "Amount she borrowed at 15.5% = $ 3597.25 \r
\n" ); document.write( "\n" ); document.write( "Amount she borrowed at 14.25 % = 6000 - 3597.25
\n" ); document.write( " = $ 2402.75
\n" ); document.write( "
\n" );