document.write( "Question 166780: log^2 (x^2-6x) = 3+log^2(1-x) \n" ); document.write( "
Algebra.Com's Answer #122893 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming when you say log^2, you mean log base 2.
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\n" ); document.write( "log2(x^2-6x) = 3+log2(1-x)
\n" ); document.write( "log2(x^2-6x) - log2(1-x) = 3
\n" ); document.write( "log2[(x^2-6x)/(1-x)] = 3
\n" ); document.write( "(x^2-6x)/(1-x) = 2^3
\n" ); document.write( "(x^2-6x)/(1-x) = 8
\n" ); document.write( "(x^2-6x) = 8(1-x)
\n" ); document.write( "x^2-6x = 8-8x
\n" ); document.write( "x^2+2x = 8
\n" ); document.write( "x^2+2x-8 = 0
\n" ); document.write( "(x+4)(x-2) = 0
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\n" ); document.write( "x = {-4, 2}\r
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