document.write( "Question 166706: Jake invested one-third of his money at 9.75% and the rest at 11.5%. At the end of 18 months he had earned $4,912.50 in simple interest. Find the total amount of money invested. \n" ); document.write( "

Algebra.Com's Answer #122888 by aswathytony(47) $\"\"$ $\"About$

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Let x be the total amount of money invested.
\n" ); document.write( "given,one third invested in 9.75%
\n" ); document.write( "i.e. x/ 3 amount invested in 9.75 %\r
\n" ); document.write( "\n" ); document.write( "rest of money= x - x /3 = x ( 1 - 1/3 )
\n" ); document.write( " = x . 2/3
\n" ); document.write( " 2/3 x \r
\n" ); document.write( "\n" ); document.write( "i.e. 2/3 x of total amount invested in 11.5%\r
\n" ); document.write( "\n" ); document.write( "given total amount = $4912.50 \r
\n" ); document.write( "\n" ); document.write( " Total amount = principal + interest ( SI = pnr/100 ) n= 18month = 3/2yrs\r
\n" ); document.write( "\n" ); document.write( " 4912.50 = x + [ (x/3 * 3/2 * 9.75 )/100 + (2/3x * 3/2 *11.5)100]\r
\n" ); document.write( "\n" ); document.write( " = x + 0.39 x /8 +2.3x /20 (canceling common terms in each
\n" ); document.write( "term)\r
\n" ); document.write( "\n" ); document.write( " 4912.50 = 40 x + 1.95 x + 4.6x /40 ( taking LCM & Multiplying)
\n" ); document.write( " =46.55x /40
\n" ); document.write( " 4912.50 * 40 =46.55x
\n" ); document.write( " 196,500 = 46.55x\r
\n" ); document.write( "\n" ); document.write( " x = 196500/46.55
\n" ); document.write( " = 4221.27
\n" ); document.write( "Amount invested = $4221.27 \n" ); document.write( "

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